2. Ȳ»êö(¥±)¾Ï¸ð´½ÀÇ ¼øµµ(%) °è»ê

    ´ÙÀ½ ½ÄÀ¸·Î öÀÇ ÇÔÀ¯À²°ú Ȳ»êö(¥±)¾Ï¸ð´½ÀÇ ¼øµµ¸¦ °è»êÇÑ´Ù.

    2KMn04 + 10Fe(NH4)2(SO4)2 + 8H2SO4 ¡æ

    K2SO4 + 2MnSO4 + 5Fe2(SO4)3 + 10(NH4)2SO4 + 8H2O

              KMn04
         = ---------- =  Fe(NH4)2(SO4)2·6H2O= Fe
                 5              

        0.1N-KMn04 = 0.039214g =  Fe(NH4)2(SO4)2·6H2O = 0.0055847g Fe

    ¨ç ö(Fe)ÀÇ ÇÔÀ¯À²(%)

               0.0055847 × f × V × (250.00/25.00)
         = ----------------------------------- × 100
                 È²»êö(¥±)¾Ï¸ð´½ÀÇ Ã¤Ãë·®(g)              

    ¨è Ȳ»êö(¥±)¾Ï¸ð´½ÀÇ ¼øµµ(%)

              0.039214 ×  × V × (250.00/25.00)
         = ----------------------------------- × 100
                 È²»êö(¥±)¾Ï¸ð´½ÀÇ Ã¤Ãë·®(g)

   ¨é ö(Fe)ÀÇ ÀÌ·Ð ÇÔÀ¯·®(%)

                                    FeÀÇ ºÐÀÚ·®
         = ----------------------------------- × 100
                    È²»êö(¥±)¾Ï¸ð´½ÀÇ ºÐÀÚ·®